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Length imperial. Weight lb. Currency USD. Weight uses 1 lb = 0.45359237 kg. Currency converts US-dollar planning prices and does not change volumes, counts, or geometry.

15 Amp Lighting Run Voltage Drop at 100 Feet

A 100 ft, 120 V lighting circuit at 15 A and a 3 percent limit.

Formula SSC-2026.1

K method · SSC-2026.1

Minimum size

8 AWG · 8.37 mm²

Single conductor set

Voltage drop

2.34 V

1.95% · end 117.7 V

Power loss

35 W

I²R at the operating current

Required ampacity

15.0 A

Each conductor 50 A

Material estimate

$588.00

3 conductors + EMT

Conductor weight

19.2 lb

8.7 kg · approximate insulated weight

Single-line and conductor gaugeLive scaled blueprint
MAIN PANELSingle-phase 120 VEMT · 100 ft · 8 AWG · 8.37 mm²Lighting15 ASelected gauge8 AWGaluminum6 AWGDrop 1.95%End 117.7 VLoss 35 W

Circle diameters track circular mils. The drawing is a schematic, not a conduit-fill layout.

Bill of materials and shopping list
ItemNetWasteOrderUnit priceLine total
copper 8 AWG · 8.37 mm²100 ft one waycuts excluded3 conductorsUSD$403.00
EMT conduit100 ft—100 ftUSD$185.00
Copper versus aluminum at this run
MaterialMinimum sizemm²DropEnd voltageLoss
copper8 AWG · 8.37 mm²8.41.95%117.7 V35 W
aluminum6 AWG · 13.3 mm²13.32.02%117.6 V36 W
Same load at other one-way distances
DistanceMinimum sizeDropPercentEnd voltage
50 ft12 AWG · 3.31 mm²2.96 V2.47%117.0 V
75 ft10 AWG · 5.26 mm²2.80 V2.33%117.2 V
100 ft8 AWG · 8.37 mm²2.34 V1.95%117.7 V
150 ft8 AWG · 8.37 mm²3.52 V2.93%116.5 V
Show the deterministic formula

Single phase: Vdrop = 2 × K × I × D / cmil. Three phase: Vdrop = 1.732 × K × I × D / cmil. K is 12.9 for copper and 21.2 for aluminum. D is one-way feet.

Percent drop = Vdrop ÷ source voltage × 100. Green is 3% or less, amber is 3 to 5%, and red is over 5%. Power loss is I²R on the current-carrying conductors.

The smallest conductor that meets both the ampacity (125% when continuous) and the drop limit is selected. Ampacity does not include bundling or temperature correction.

Engineering notes

Fourteen AWG copper is limited to 15 A, so it passes ampacity for this circuit and then fails the drop. At 100 ft and 120 V the calculator steps through 12 and 10 AWG until the drop is inside 3 percent. That is the point of the page: breaker size and wire size are different questions on a long lighting homerun. The load is modeled at the full 15 A even if the lamps draw less. Lower the amps if you know the actual load.

Code reference

NEC 210.19(A) and 215.2(A) informational notes recommend 3 percent on a branch circuit and 5 percent total with the feeder. Ampacity follows the 75°C column of Table 310.16 plus the small-conductor limits. Confirm the adopted edition.

Field questions

Can I keep 14 AWG if the lights draw less than 15 amps?
Type the actual load. Drop is proportional to current. A circuit loaded to 8 A loses less voltage than the same wire at 15 A.
What does the red or amber badge mean?
Green is 3 percent or less, amber is between 3 and 5 percent, and red is above 5 percent.
Is the loss number the lamp wattage?
No. It is I²R heating in the conductors, not the power used by the lights.